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The equation provided is:

\[
-2(y + 3) + 3(2y - 1) = 10
\]

Let's solve for \( y \) step by step:

1. **Distribute the coefficients**:
   \[
   -2 \times (y + 3) + 3 \times (2y - 1) = 10
   \]
   \[
   -2y - 6 + 6y - 3 = 10
   \]

2. **Combine like terms**:
   \[
   (-2y + 6y) + (-6 - 3) = 10
   \]
   \[
   4y - 9 = 10
   \]

3. **Isolate the variable \( y \)**:
   \[
   4y = 10 + 9
   \]
   \[
   4y = 19
   \]

4. **Solve for \( y \)**:
   \[
   y = \frac{19}{4}
   \]
   \[
   y = 4.75
   \]

So, the solution is \( y = 4.75 \).

Would you like any more details or explanations? 

Here are some related questions:
1. How do you verify if a solution is correct for an equation?
2. Can this equation be solved using another method, like substitution or elimination?
3. What is the importance of distributing in algebraic equations?
4. How can equations like this be applied in real-life scenarios?
5. What happens if you forget to combine like terms?

**Tip:** Always double-check your calculations, especially when distributing or combining like terms, to ensure accuracy.

Learn how to solve the equation -2(y + 3) + 3(2y - 1) = 10 with a detailed step-by-step solution. This problem covers key algebraic concepts such as the distributive property and combining like terms. Suitable for students in Grades 7-9.

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