$$  $$$$ 2a+3\left(23\right)+4\left(2^3\right)=2n\text{ maka nilai n} $$

We are given the equation:

\[
2a + 3(23) + 4(2^3) = 2n
\]

We need to find the value of $ n $. Let's solve the equation step by step:

### Step 1: Simplify the parentheses

- $ 3(23) = 69 $
- $ 2^3 = 8 $, so $ 4(2^3) = 4 \times 8 = 32 $

Now, the equation becomes:

\[
2a + 69 + 32 = 2n
\]

### Step 2: Combine constants

\[
2a + 101 = 2n
\]

### Step 3: Solve for $ n $

Divide the equation by 2 on both sides to isolate $ n $:

\[
n = \frac{2a + 101}{2}
\]

So, the value of $ n $ in terms of $ a $ is:

\[
n = a + \frac{101}{2}
\]

If $ a $ is an integer, then $ n $ will also be a fraction unless $ 101 $ is divisible by 2. However, since it's not divisible, the final result remains $ n = a + \frac{101}{2} $.

---

Would you like further details or have any other questions about this solution?

### Related Questions:
1. What happens if $ a = 0 $? How does $ n $ change?
2. Can you calculate $ n $ for any specific value of $ a $?
3. How does this expression change if we make $ a $ a negative number?
4. How do we approach similar equations with exponents higher than 3?
5. What if we replaced 2 with another coefficient? How would that affect the outcome?

### Tip:
When simplifying complex equations, always start by handling the powers and parentheses first to make calculations easier.

Learn how to solve the equation 2a + 3(23) + 4(2^3) = 2n and find the value of n with a detailed step-by-step explanation. This problem involves algebraic simplifications and exponentiation, suitable for students in Grades 6-8.

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