Let's solve the expression step by step.

The expression is:

\[
(2^2)^{-3} \times 4^4
\]

1. **First, calculate \(2^2\):**

\[
2^2 = 4
\]

2. **Now, raise 4 to the power of -3:**

\[
4^{-3} = \frac{1}{4^3} = \frac{1}{64}
\]

3. **Next, calculate \(4^4\):**

\[
4^4 = 256
\]

4. **Finally, multiply the results:**

\[
\frac{1}{64} \times 256 = \frac{256}{64} = 4
\]

So, the final result of the expression is \( \boxed{4} \).

Would you like further details or have any questions?

Here are five related questions to expand your understanding:

1. What is the general rule for calculating negative exponents?
2. How does the order of operations (PEMDAS) apply to expressions with exponents and multiplication?
3. What happens when you multiply numbers with the same base but different exponents?
4. How can you simplify expressions involving fractional exponents?
5. What is the significance of zero as an exponent in any expression?

**Tip:** When dealing with negative exponents, remember that it indicates the reciprocal of the base raised to the positive exponent.

Learn how to solve the expression (2^2)^-3*4^4 step by step with detailed explanations. This problem involves exponents and multiplication of exponents, covering key concepts in algebra and arithmetic. Suitable for Grades 7-9 students.

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