Let's solve the expression \(2 \times 2 \times 6^2 - 2^2\).

1. First, calculate \(6^2\):
   \[
   6^2 = 36
   \]

2. Multiply \(2 \times 2 \times 36\):
   \[
   2 \times 2 = 4
   \]
   \[
   4 \times 36 = 144
   \]

3. Then, calculate \(2^2\):
   \[
   2^2 = 4
   \]

4. Finally, subtract \(2^2\) from the previous result:
   \[
   144 - 4 = 140
   \]

The result of the expression \(2 \times 2 \times 6^2 - 2^2\) is **140**.

Would you like any further details or have any questions?

Here are 5 related questions:
1. What is the value of \(3 \times 2 \times 5^2 - 3^2\)?
2. How does the expression change if we add \(3^2\) at the end instead of subtracting \(2^2\)?
3. What would be the result if we replace \(6^2\) with \(7^2\) in the expression?
4. How does multiplying by a different constant, like \(3 \times 2 \times 6^2\), affect the result?
5. What happens if you switch the order of operations in the expression \(2 \times (2 \times 6)^2 - 2^2\)?

**Tip:** Breaking down complex expressions into smaller steps can help avoid errors and make solving them easier.

Learn how to solve the expression 2(2)(6)^2 - 2^2 with a detailed step-by-step solution. This problem covers arithmetic operations and exponents, demonstrating how to calculate powers and perform multiplication and subtraction. Suitable for students in Grades 5-6.

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