https://file.aiquickdraw.com/mathbot/file/1725609255035u72wdkwu.jpg

The problem in the image states:

- \( P(A) = 0.5 \)
- \( P(B) = 0.2 \)
- Events \( A \) and \( B \) are mutually exclusive.

We need to find \( P(A \text{ or } B) \), which is written as \( P(A \cup B) \).

Since \( A \) and \( B \) are mutually exclusive, the formula to compute \( P(A \cup B) \) is:

\[
P(A \cup B) = P(A) + P(B)
\]

Now, substituting the given values:

\[
P(A \cup B) = 0.5 + 0.2 = 0.7
\]

Thus, \( P(A \cup B) = 0.7 \).

Let me know if you need further details or explanations. Here are 5 related questions:

1. How would the formula change if \( A \) and \( B \) were not mutually exclusive?
2. What is the definition of mutually exclusive events?
3. How do you calculate \( P(A \cup B) \) for independent events?
4. What would \( P(A \cap B) \) be if \( A \) and \( B \) were mutually exclusive?
5. Can the probability of an event ever exceed 1?

**Tip:** For mutually exclusive events, the probability of both events occurring at the same time is always zero.

If P(A) = 0.5, P(B) = 0.2, and A and B are mutually exclusive, find P(A or B).

Learn how to calculate the probability of mutually exclusive events with P(A) = 0.5 and P(B) = 0.2. This example uses the additive rule to find P(A or B). Suitable for Grades 10-12.

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