Let
and
be mutually exclusive events, such that
and
. Find the following probabilities:

P(A and B)=
% (Round the answer to 2 decimals)

P(A or B)=
% (Round the answer to 2 decimals)

To solve these probabilities, let's use the following standard probability rules:

- For mutually exclusive events, \( P(A \text{ and } B) = 0 \). This is because mutually exclusive events cannot happen at the same time.

- For the probability of \( P(A \text{ or } B) \), use the formula:
\[
P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B)
\]
Since \( P(A \text{ and } B) = 0 \), the formula simplifies to:
\[
P(A \text{ or } B) = P(A) + P(B)
\]

Now let's solve:

1. \( P(A \text{ and } B) = 0 \)
2. \( P(A \text{ or } B) = P(A) + P(B) \)

To finalize the calculations, I need the values of \( P(A) \) and \( P(B) \). Could you provide those probabilities?

Let A and B be mutually exclusive events, such that P(A) and P(B). Find the following probabilities: P(A and B)= % (Round the answer to 2 decimals) P(A or B)= % (Round the answer to 2 decimals).

Solve for the probabilities of mutually exclusive events A and B using key probability formulas. Learn how to calculate P(A and B) and P(A or B) with step-by-step explanations. This problem is suitable for students in Grades 9-11.

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