Math Problem Statement

Events A and B are mutually exclusive.  Find the probability of A or B.  Express all the solution as a reduced fraction in the form a/b.

P(A) = 1/2  and P(B) = 1/4

P(A or B) =

Solution

To find the probability of either event A or event B occurring when the events are mutually exclusive, we use the formula:

P(A or B)=P(A)+P(B)P(A \text{ or } B) = P(A) + P(B)

Given: P(A)=12P(A) = \frac{1}{2} P(B)=14P(B) = \frac{1}{4}

Since the events are mutually exclusive, we can simply add the probabilities:

P(A or B)=12+14P(A \text{ or } B) = \frac{1}{2} + \frac{1}{4}

To add these fractions, find a common denominator. The least common denominator (LCD) of 2 and 4 is 4.

Convert 12\frac{1}{2} to have a denominator of 4:

[ \frac{1