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Box A and Box B contained 154 and 72 oranges respectively. Jean transferred some oranges from Box A into Box B so that Box A had 24 more oranges than Box B in the end. How many oranges were in each box in the end?

To solve this problem, let's denote the number of oranges transferred from Box A to Box B as \( x \).

Initially:
- Box A has 154 oranges.
- Box B has 72 oranges.

After transferring \( x \) oranges from Box A to Box B:
- Box A will have \( 154 - x \) oranges.
- Box B will have \( 72 + x \) oranges.

We are given that in the end, Box A has 24 more oranges than Box B. Therefore, we can set up the following equation:
\[ 154 - x = (72 + x) + 24 \]

Let's solve for \( x \):
\[ 154 - x = 72 + x + 24 \]
\[ 154 - x = 96 + x \]
\[ 154 - 96 = x + x \]
\[ 58 = 2x \]
\[ x = 29 \]

So, Jean transferred 29 oranges from Box A to Box B.

Now, we can find the number of oranges in each box in the end:
- Box A: \( 154 - 29 = 125 \) oranges.
- Box B: \( 72 + 29 = 101 \) oranges.

Therefore, in the end:
- Box A has 125 oranges.
- Box B has 101 oranges.

Would you like further details or have any questions? Here are some more questions you might be interested in:

1. How would the equation change if Jean transferred 10 more oranges?
2. What if Box B initially had 100 oranges instead of 72?
3. How many oranges would each box have if Jean wanted Box A to have 30 more oranges than Box B in the end?
4. Can you create a general formula for any initial number of oranges in Box A and Box B?
5. How many oranges need to be transferred if the difference in the end should be 50 oranges instead?

**Tip:** Always verify your final answer by substituting back into the original conditions to ensure consistency.

Explore how to solve a word problem involving oranges in boxes. Find out how many oranges were in each box after Jean transferred some between them. Learn about equations, arithmetic operations, and problem-solving strategies. Suitable for Grades 5-7.

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