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Let's solve the problem step by step:

1. **Define variables:**
   - Let \( x \) be the number of boxes with 8 books.
   - Let \( y \) be the number of boxes with 12 books.
   
2. **Given information:**
   - The total number of books is 140.
   - There are equal numbers of both types of boxes, so \( x = y \).

3. **Set up the equation:**
   - Each box with 8 books contributes \( 8x \) books.
   - Each box with 12 books contributes \( 12y \) books.
   - Since \( x = y \), let's call this common number \( n \).
   - So, the total number of books can be expressed as: \( 8n + 12n = 140 \).

4. **Simplify the equation:**
   \[
   20n = 140
   \]
   \[
   n = \frac{140}{20} = 7
   \]

So, there are 7 boxes holding 12 books each.

Would you like a detailed breakdown or have any questions about this solution?

Here are some related questions you might find interesting:

1. If there were 160 books, how many boxes of each type would be sent?
2. What would happen if the numbers of each type of box were not equal?
3. If a third type of box held 6 books, how would the equation change?
4. How many books would be packed if only 8-book boxes were used?
5. What is the total weight if each book weighs 0.5 kg?

**Tip:** Breaking down a word problem into equations and simplifying systematically helps avoid mistakes and makes complex problems easier to handle!

A publisher sent 140 copies of a book to a shop. The publisher packed the books in two types of boxes. One type of box held 8 copies of the book. The other type of box held 12 copies of the book. The boxes were all full. There were equal numbers of both types of boxes. Work out how many boxes holding 12 books were sent to the shop.

Learn how to solve a word problem involving the distribution of 140 books into boxes with equal numbers of two types. Understand the use of linear equations and algebraic concepts in finding the solution. Suitable for Grades 6-8.

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