Oranges cost 25 cents each and apples cost 30 cents each. I bought 5 more oranges than apples, and the total cost was 4.55$. how many apples did I buy

Let's define the number of apples you bought as $ x $.

Since you bought 5 more oranges than apples, the number of oranges is $ x + 5 $.

The cost of each apple is 30 cents, so the total cost of the apples is $ 0.30x $.

The cost of each orange is 25 cents, so the total cost of the oranges is $ 0.25(x + 5) $.

The total cost of the apples and oranges combined is $4.55, which can be written as 4.55 in dollars.

We can now set up the equation for the total cost:

\[
0.30x + 0.25(x + 5) = 4.55
\]

Let's solve this step-by-step:

\[
0.30x + 0.25x + 1.25 = 4.55
\]

Combine like terms:

\[
0.55x + 1.25 = 4.55
\]

Subtract 1.25 from both sides:

\[
0.55x = 3.30
\]

Now, divide both sides by 0.55:

\[
x = \frac{3.30}{0.55} = 6
\]

So, you bought **6 apples**.

Would you like more details or have any questions?

Here are some related questions:
1. How many oranges did I buy?
2. What would be the total cost if I bought 7 apples instead?
3. How would the equation change if oranges cost 30 cents and apples 25 cents?
4. What is the total number of fruits I bought?
5. What if the total cost was $5 instead of $4.55?

**Tip:** Always check your solution by plugging values back into the original equation to ensure correctness.

Oranges cost 25 cents each and apples cost 30 cents each. I bought 5 more oranges than apples, and the total cost was 4.55$. How many apples did I buy?

Learn how to solve a linear equation problem involving the cost of apples and oranges. This problem demonstrates basic algebra concepts and equation solving, suitable for students in Grades 6-8. The solution shows step-by-step how to calculate the number of apples bought.

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