Math Problem Statement

The table below gives the list price and the number of bids received for five randomly selected items sold through online auctions. Using this data, consider the equation of the regression line, yˆ=b0+b1x , for predicting the number of bids an item will receive based on the list price. Keep in mind, the correlation coefficient may or may not be statistically significant for the data given. Remember, in practice, it would not be appropriate to use the regression line to make a prediction if the correlation coefficient is not statistically significant.

Price in Dollars 20 39 43 44 47 Number of Bids 3 5 8 9 10 Table

Step 3 of 6 : Substitute the values you found in steps 1 and 2 into the equation for the regression line to find the estimated linear model. According to this model, if the value of the independent variable is increased by one unit, then find the change in the dependent variable yˆ .

Solution

To solve this problem, we need to follow these steps:

Step 1: Find the regression coefficients b0b_0 (intercept) and b1b_1 (slope).

We will use the following formulas to calculate these coefficients:

  1. Slope b1b_1: b1=n(xiyi)xiyinxi2(xi)2b_1 = \frac{n \sum{(x_i y_i)} - \sum{x_i} \sum{y_i}}{n \sum{x_i^2} - (\sum{x_i})^2}

  2. Intercept b0b_0: b0=yib1xinb_0 = \frac{\sum{y_i} - b_1 \sum{x_i}}{n}

Where:

  • xix_i = List price
  • yiy_i = Number of bids
  • nn = Number of data points (which is 5 in this case)

Step 2: Let's calculate the necessary sums from the given data:

Price xix_iBids yiy_ixiyix_i y_ixi2x_i^2
20360400
3951951521
4383441849
4493961936
47104702209

Now, let's calculate the necessary sums:

  • xi=20+39+43+44+47=193\sum x_i = 20 + 39 + 43 + 44 + 47 = 193
  • yi=3+5+8+9+10=35\sum y_i = 3 + 5 + 8 + 9 + 10 = 35
  • (xiyi)=60+195+344+396+470=1465\sum (x_i y_i) = 60 + 195 + 344 + 396 + 470 = 1465
  • (xi2)=400+1521+1849+1936+2209=7915\sum (x_i^2) = 400 + 1521 + 1849 + 1936 + 2209 = 7915

Step 3: Apply the formulas to calculate b1b_1 and b0b_0.

  1. Calculate b1b_1: b1=5×1465193×355×7915(193)2b_1 = \frac{5 \times 1465 - 193 \times 35}{5 \times 7915 - (193)^2} b1=732567553957537249b_1 = \frac{7325 - 6755}{39575 - 37249} b1=5702326b_1 = \frac{570}{2326} b10.245b_1 \approx 0.245

  2. Calculate b0b_0: b0=350.245×1935b_0 = \frac{35 - 0.245 \times 193}{5} b0=3547.3355b_0 = \frac{35 - 47.335}{5} b0=12.3355b_0 = \frac{-12.335}{5} b02.467b_0 \approx -2.467

Step 4: The estimated regression equation is:

y^=2.467+0.245x\hat{y} = -2.467 + 0.245x

Step 5: Interpretation of the coefficients:

  • Slope (b1b_1): The slope is 0.245, meaning that for every 1 unit increase in the price (x), the number of bids (y) increases by approximately 0.245.
  • Intercept (b0b_0): The intercept is -2.467, which is the estimated number of bids when the price is 0 (though this is not practically relevant in this case, since prices cannot be 0).

Step 6: If the price increases by 1 unit (say, 1 dollar), the change in the number of bids y^\hat{y} would be a 0.245 increase in the number of bids.


Would you like more details about the regression analysis, or do you have any questions? Here are some related questions:

  1. What would the estimated number of bids be for a price of $50?
  2. How do you interpret the intercept value in this regression model?
  3. How can we assess the strength of this regression model using the correlation coefficient?
  4. How would this regression equation change if we added more data points?
  5. What other factors might influence the number of bids in online auctions?

Tip: Always check the significance of your regression coefficients (especially b1b_1) before making predictions.

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Math Problem Analysis

Mathematical Concepts

Regression Analysis
Linear Models
Correlation Coefficient

Formulas

b1 = (n * Σ(xi * yi) - Σxi * Σyi) / (n * Σ(xi^2) - (Σxi)^2)
b0 = (Σyi - b1 * Σxi) / n

Theorems

Least Squares Regression
Linear Regression Analysis

Suitable Grade Level

Grades 10-12