Math Problem Statement

The table below gives the list price and the number of bids received for five randomly selected items sold through online auctions. Using this data, consider the equation of the regression line, yˆ=b0+b1x , for predicting the number of bids an item will receive based on the list price. Keep in mind, the correlation coefficient may or may not be statistically significant for the data given. Remember, in practice, it would not be appropriate to use the regression line to make a prediction if the correlation coefficient is not statistically significant.

Price in Dollars 21 27 31 43 49 Number of Bids 4 6 7 8 9 Table

Step 3 of 6 : Find the estimated value of y when x=27 . Round your answer to three decimal places.

Solution

To find the estimated value of yy when x=27x = 27, we need to follow these steps:

  1. Calculate the regression line y^=b0+b1x\hat{y} = b_0 + b_1 x, where:
    • b1b_1 is the slope of the regression line, and
    • b0b_0 is the y-intercept.

Step 1: Calculate the slope b1b_1 and intercept b0b_0

We use the formulas for the slope and intercept of the regression line:

b1=nxyxynx2(x)2b_1 = \frac{n \sum xy - \sum x \sum y}{n \sum x^2 - (\sum x)^2} b0=yb1xnb_0 = \frac{\sum y - b_1 \sum x}{n}

Where:

  • nn is the number of data points,
  • x\sum x is the sum of all the xx-values (prices),
  • y\sum y is the sum of all the yy-values (number of bids),
  • xy\sum xy is the sum of the product of corresponding xx- and yy-values,
  • x2\sum x^2 is the sum of the squares of the xx-values.

Step 2: Set up the data and compute the necessary values

Given data:

  • xx (prices): 21, 27, 31, 43, 49
  • yy (number of bids): 4, 6, 7, 8, 9

We will compute the sums:

  • x=21+27+31+43+49=171\sum x = 21 + 27 + 31 + 43 + 49 = 171
  • y=4+6+7+8+9=34\sum y = 4 + 6 + 7 + 8 + 9 = 34
  • x2=212+272+312+432+492=441+729+961+1849+2401=5381\sum x^2 = 21^2 + 27^2 + 31^2 + 43^2 + 49^2 = 441 + 729 + 961 + 1849 + 2401 = 5381
  • xy=(21×4)+(27×6)+(31×7)+(43×8)+(49×9)=84+162+217+344+441=1248\sum xy = (21 \times 4) + (27 \times 6) + (31 \times 7) + (43 \times 8) + (49 \times 9) = 84 + 162 + 217 + 344 + 441 = 1248

Now, we can calculate the slope b1b_1 and intercept b0b_0.

Slope b1b_1:

b1=5×1248171×345×53811712b_1 = \frac{5 \times 1248 - 171 \times 34}{5 \times 5381 - 171^2}

b1=624058142690529241b_1 = \frac{6240 - 5814}{26905 - 29241}

b1=426234b_1 = \frac{426}{-234}

b1=1.82(approximately)b_1 = -1.82 \quad (\text{approximately})

Intercept b0b_0:

b0=34(1.82)×1715b_0 = \frac{34 - (-1.82) \times 171}{5}

b0=34+310.625b_0 = \frac{34 + 310.62}{5}

b0=344.625=68.924b_0 = \frac{344.62}{5} = 68.924

Step 3: Find the estimated value of yy when x=27x = 27

Now that we have b0=68.924b_0 = 68.924 and b1=1.82b_1 = -1.82, we can substitute x=27x = 27 into the regression equation:

y^=68.924+(1.82)(27)\hat{y} = 68.924 + (-1.82)(27)

y^=68.92449.14\hat{y} = 68.924 - 49.14

y^=19.784\hat{y} = 19.784

Thus, the estimated value of yy when x=27x = 27 is 19.784.

Would you like me to explain any part of the process, or is there anything else you'd like to explore? Here are some related questions for further practice:

  1. How would you interpret the slope of the regression line in this context?
  2. What would happen to the predicted number of bids if the list price were increased by $10?
  3. How do you check if the correlation coefficient is statistically significant?
  4. How would you calculate the residuals for each data point?
  5. What does the R2R^2 value tell you about the fit of the regression line?

Tip: It's always a good practice to check the residuals after fitting a regression model. They can tell you how well the model fits the data and if any patterns are left unexplained.

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Math Problem Analysis

Mathematical Concepts

Linear Regression
Statistics
Algebra

Formulas

yˆ = b0 + b1x
b1 = (n Σxy - Σx Σy) / (n Σx^2 - (Σx)^2)
b0 = (Σy - b1 Σx) / n

Theorems

Least Squares Regression
Correlation Coefficient

Suitable Grade Level

Grades 9-12