Math Problem Statement

The table below gives the list price and the number of bids received for five randomly selected items sold through online auctions. Using this data, consider the equation of the regression line, yˆ=b0+b1x , for predicting the number of bids an item will receive based on the list price. Keep in mind, the correlation coefficient may or may not be statistically significant for the data given. Remember, in practice, it would not be appropriate to use the regression line to make a prediction if the correlation coefficient is not statistically significant.

Price in Dollars 21 27 31 43 49 Number of Bids 4 6 7 8 9 Table

Step 3 of 6 : Find the estimated value of y when x=27 . Round your answer to three decimal places.

Solution

To find the estimated value of yy when x=27x = 27, we need to determine the regression equation:

y^=b0+b1x\hat{y} = b_0 + b_1x

Step 1: Compute the Slope (b1b_1)

The formula for the slope is:

b1=nxyxynx2(x)2b_1 = \frac{n\sum xy - \sum x \sum y}{n\sum x^2 - (\sum x)^2}

Given data:

Price (xx)Number of Bids (yy)xyxyx2x^2
21484441
276162729
317217961
4383441849
4994412401

Now, compute the required summations:

x=21+27+31+43+49=171\sum x = 21 + 27 + 31 + 43 + 49 = 171

y=4+6+7+8+9=34\sum y = 4 + 6 + 7 + 8 + 9 = 34

xy=84+162+217+344+441=1248\sum xy = 84 + 162 + 217 + 344 + 441 = 1248

x2=441+729+961+1849+2401=6381\sum x^2 = 441 + 729 + 961 + 1849 + 2401 = 6381

n=5n = 5

b1=(5)(1248)(171)(34)(5)(6381)(171)2b_1 = \frac{(5)(1248) - (171)(34)}{(5)(6381) - (171)^2}

b1=624058143190529241=42626640.160b_1 = \frac{6240 - 5814}{31905 - 29241} = \frac{426}{2664} \approx 0.160

Step 2: Compute the Intercept (b0b_0)

The intercept is given by:

b0=yˉb1xˉb_0 = \bar{y} - b_1\bar{x}

where

xˉ=xn=1715=34.2\bar{x} = \frac{\sum x}{n} = \frac{171}{5} = 34.2

yˉ=yn=345=6.8\bar{y} = \frac{\sum y}{n} = \frac{34}{5} = 6.8

b0=6.8(0.160)(34.2)b_0 = 6.8 - (0.160)(34.2)

b0=6.85.472=1.328b_0 = 6.8 - 5.472 = 1.328

Step 3: Predict yy when x=27x = 27

y^=1.328+(0.160)(27)\hat{y} = 1.328 + (0.160)(27)

y^=1.328+4.32=5.648\hat{y} = 1.328 + 4.32 = 5.648

Final Answer: y^5.648\hat{y} \approx 5.648

Would you like me to verify significance of the correlation coefficient?


Related Questions:

  1. How do we interpret the correlation coefficient in this context?
  2. What is the coefficient of determination (R2R^2) and how does it relate to the regression line?
  3. How can we test if the regression model is statistically significant?
  4. What are the assumptions of linear regression, and do they apply here?
  5. How do outliers impact the accuracy of a regression model?

Tip:

Always check the significance of the correlation coefficient before making predictions with a regression model. If it is not statistically significant, predictions may not be reliable.

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Math Problem Analysis

Mathematical Concepts

Linear Regression
Slope of Regression Line
Intercept of Regression Line
Prediction using Regression

Formulas

yˆ = b0 + b1x
b1 = (nΣxy - ΣxΣy) / (nΣx^2 - (Σx)^2)
b0 = ȳ - b1x̄

Theorems

Least Squares Regression Method

Suitable Grade Level

Grades 9-12