Math Problem Statement

Divya and Bhabya went to the market to buy some gifts for their friend Momita's birthday. Divya had Rs.80 in her bag while Bhabya had Rs.85. Divya had coins of denominations Rs.2 and Rs.5, Bhabya had coins of denominations Rs.1 and Rs.2 and the ratio of the number of coins of both was 5:6. Based on the above information answer the following questions. (i) Write an equation to find the number of coins in Divya's bag. (ii) Write an equation to find the number of coins in Bhabya's bag. (iii) Find the number of Rs. 2 coins in Bhabya's and also in Dibya's bag.

Solution

To solve the problem, let's break it down into parts and create equations based on the given information.

(i) Equation to find the number of coins in Divya's bag

  • Divya has Rs. 80 in total, and her coins are of denominations Rs. 2 and Rs. 5.
  • Let the number of Rs. 2 coins be xx.
  • Let the number of Rs. 5 coins be yy.

The total value of coins in Divya's bag is given by: 2x+5y=802x + 5y = 80 This is the equation to find the number of coins in Divya's bag.

(ii) Equation to find the number of coins in Bhabya's bag

  • Bhabya has Rs. 85 in total, and her coins are of denominations Rs. 1 and Rs. 2.
  • Let the number of Rs. 1 coins be mm.
  • Let the number of Rs. 2 coins be nn.

The total value of coins in Bhabya's bag is given by: 1m+2n=85or simplym+2n=851m + 2n = 85 \quad \text{or simply} \quad m + 2n = 85

Additionally, it is mentioned that the ratio of the number of Rs. 1 coins to Rs. 2 coins is 5:6, which gives us another equation: mn=56\frac{m}{n} = \frac{5}{6} or equivalently: 6m=5n6m = 5n

(iii) Find the number of Rs. 2 coins in both Divya's and Bhabya's bags

For Divya's bag, we already have the equation: 2x+5y=802x + 5y = 80 We need more information to solve this, such as another equation to relate xx and yy, which could be derived from additional constraints.

For Bhabya's bag, we have the system of equations:

  1. m+2n=85m + 2n = 85
  2. 6m=5n6m = 5n

Substituting m=5n6m = \frac{5n}{6} into the first equation: 5n6+2n=85\frac{5n}{6} + 2n = 85 Multiplying the whole equation by 6 to eliminate the fraction: 5n+12n=5105n + 12n = 510 17n=51017n = 510 n=30n = 30

So, Bhabya has 30 Rs. 2 coins. Substituting n=30n = 30 into m=5n6m = \frac{5n}{6}: m=5×306=25m = \frac{5 \times 30}{6} = 25 So Bhabya has 25 Rs. 1 coins.

Now, to determine the number of Rs. 2 coins in Divya's bag, we would need to solve 2x+5y=802x + 5y = 80 with additional information about either xx or yy.


Do you want further details on solving Divya's equation or any other questions about this problem?

Related questions:

  1. How many total coins are in Bhabya's bag?
  2. What is the ratio of total coins between Divya and Bhabya?
  3. Can you find the number of Rs. 5 coins in Divya's bag?
  4. What if Bhabya had Rs. 100 instead of Rs. 85? How would the equations change?
  5. Can you verify the ratio of the Rs. 1 to Rs. 2 coins for Bhabya?

Tip:

When dealing with word problems, it's helpful to define all variables clearly and create equations from the relationships described in the problem.

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Math Problem Analysis

Mathematical Concepts

Algebra
Ratio and Proportion
Linear Equations

Formulas

2x + 5y = 80 (Divya's equation)
m + 2n = 85 (Bhabya's equation)
6m = 5n (Ratio of Bhabya's coins)

Theorems

Basic principles of linear equations
Ratio and Proportion theorem

Suitable Grade Level

Grades 6-8