Jim has $5 more than sue, and sue has $11 more than johnny. Together they have $45. How much does each have

Let's define the variables based on the information provided:

- Let $ J $ be the amount Johnny has.
- Sue has $11 more than Johnny, so Sue has $ J + 11 $.
- Jim has $5 more than Sue, so Jim has $ (J + 11) + 5 = J + 16 $.

Now, the total amount they have together is $45, which gives us the equation:

\[
J + (J + 11) + (J + 16) = 45
\]

Simplifying the equation:

\[
J + J + 11 + J + 16 = 45
\]

\[
3J + 27 = 45
\]

Subtract 27 from both sides:

\[
3J = 18
\]

Divide by 3:

\[
J = 6
\]

Now that we know Johnny has $6, we can find out how much Sue and Jim have:

- Sue has $ J + 11 = 6 + 11 = 17 $.
- Jim has $ J + 16 = 6 + 16 = 22 $.

### Final amounts:
- Johnny: $6
- Sue: $17
- Jim: $22

Would you like more details or have any questions?

Here are 5 related questions for further practice:
1. If Jim had $10 more than Sue, what would their total amount be?
2. What if Sue had $20 more than Johnny, and together they had $50, how much would each have?
3. How would the solution change if the total was $60 but all other conditions remained the same?
4. If Jim gave $3 to Sue, how much would they have individually now?
5. If Johnny saved $4 more, how would the total change?

**Tip:** When working with word problems, assigning variables to unknowns and building equations based on relationships helps simplify the problem.

Jim has $5 more than Sue, and Sue has $11 more than Johnny. Together they have $45. How much does each have?

Learn how to solve a word problem where Jim has $5 more than Sue, and Sue has $11 more than Johnny. Together, they have $45. This algebraic solution helps break down linear equations step by step. Suitable for students in Grades 6-8.

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