Math Problem Statement

Luke had $111 at first. After Jennifer spent $43, Luke had 3 times as much money as Jennifer. How much more money did Luke have than Jennifer at first?

Solution

To solve the problem in the image, let's analyze the situation step by step.

Problem Summary:

  • Luke initially had $111.
  • After Jennifer spent $43, Luke had 3 times as much money as Jennifer.
  • We need to find out how much more money Luke had than Jennifer at first.

Steps to Solve:

  1. Let JJ be the amount of money Jennifer had initially.

  2. After Jennifer spent $43, she has J43J - 43 left.

  3. According to the problem, Luke's money is 3 times Jennifer's remaining money: 111=3×(J43)111 = 3 \times (J - 43)

  4. Now, solve the equation for JJ: 111=3×(J43)111 = 3 \times (J - 43) Divide both sides by 3: 37=J4337 = J - 43 Add 43 to both sides: J=80J = 80

    So, Jennifer had $80 initially.

  5. Determine how much more money Luke had than Jennifer initially: 11180=31111 - 80 = 31 Therefore, Luke had $31 more than Jennifer at first.

Final Answer:

Luke had $31 more than Jennifer at first.

Would you like more details or have any questions?

Here are some related questions for further practice:

  1. If Jennifer had $100 initially, how much did she have left after spending $43?
  2. How much money did Luke have after Jennifer spent $43?
  3. If Luke had 4 times as much money as Jennifer after her spending, what would Jennifer's initial amount be?
  4. What if Jennifer spent $50 instead? How would that change the problem?
  5. Can you create a similar problem but with different numbers and solve it?

Tip: When solving problems involving comparisons like "3 times as much," always set up the equation carefully to relate the amounts.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations

Formulas

Equation of the form A = k(B - C)
Basic arithmetic operations

Theorems

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Suitable Grade Level

Grades 5-6