Math Problem Statement

I'm confused. explain very simple why are we using inverse??

Solution

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Right Triangle
Inverse Functions

Formulas

\( \tan \theta = \frac{\text{Opposite}}{\text{Adjacent}} \)
\( \theta = \tan^{-1} \left( \frac{\text{Opposite}}{\text{Adjacent}} \right) \)

Theorems

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Suitable Grade Level

Grades 9-12