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The question in the image is about a ball experiencing free fall from a height of 60 meters, with acceleration due to gravity \( g = 10 \, \text{m/s}^2 \). It asks for the height of the object after \( t = 2 \) seconds.

### Step-by-step solution:

1. **Given:**
   - Initial height \( h_0 = 60 \, \text{m} \)
   - Gravity \( g = 10 \, \text{m/s}^2 \)
   - Time \( t = 2 \, \text{seconds} \)
   
2. **Free-fall equation:**
   The height of an object under free fall after time \( t \) can be found using the equation:
   \[
   h(t) = h_0 - \frac{1}{2} g t^2
   \]
   Where:
   - \( h_0 \) is the initial height,
   - \( g \) is the acceleration due to gravity,
   - \( t \) is the time.

3. **Substitute the values:**
   \[
   h(2) = 60 - \frac{1}{2} \times 10 \times (2)^2
   \]
   \[
   h(2) = 60 - \frac{1}{2} \times 10 \times 4
   \]
   \[
   h(2) = 60 - 20
   \]
   \[
   h(2) = 40 \, \text{m}
   \]

So, the correct height of the ball after 2 seconds is **40 meters**.

### Correct answer:
The correct choice is **40 meters**.

Do you want further details or have any questions? Here are five related questions to explore:

1. How do we derive the equation of free fall?
2. What happens to the height if the gravitational acceleration changes?
3. How would the height be different if the initial velocity was not zero?
4. Can we use the same formula if the object was thrown upwards instead of falling?
5. How does air resistance affect the motion of a freely falling object?

**Tip:** In free fall, the only force acting on the object is gravity, assuming no air resistance.

Sebuah bola mengalami gerak jatuh bebas dari ketinggian 60 m (g = 10 ms^-2). Maka tinggi benda saat t = 2 s adalah...

Solve a free fall problem where a ball is dropped from a height of 60 meters with a gravitational acceleration of 10 m/s². Find the height of the object after 2 seconds using kinematic equations. Suitable for Grades 9-10.

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