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The problem states the following:

- The equation is \( d = r \cdot t \), where:
  - \( r \) is the average rate of speed in **feet per second**.
  - \( t \) is time in **seconds**.
  
You are asked to determine the units of \( d \) when \( d \) is the distance traveled.

### Solution:
- \( r \) is measured in **feet per second (ft/s)**.
- \( t \) is measured in **seconds (s)**.

Multiplying these units:

\[
d = (r \cdot t) = \left( \frac{\text{ft}}{\text{s}} \right) \times \text{s} = \text{ft}
\]

So, \( d \) (the distance) is measured in **feet**.

Thus, the correct answer is:

**C. feet**

Would you like any more details or further clarification?

Here are 5 related questions to consider:
1. What is the general form of the equation for distance, rate, and time?
2. How do units cancel out when multiplying rates and time?
3. If the speed is given in meters per second and time in seconds, what would the distance be measured in?
4. How would the equation change if the rate was given in miles per hour?
5. How can dimensional analysis help ensure equations are consistent in terms of units?

**Tip:** Always check units in equations to ensure consistency and correctness.

The distance, d, an object travels is represented by the equation d = r * t, where r represents the average rate of speed and t represents time. Determine the units of d if d is measured in feet and r is measured in feet per second.

Learn how to determine the units of distance in a problem where speed is given in feet per second and time in seconds. This involves applying the distance formula (d = r * t) and understanding unit conversions for physical quantities. Ideal for students in Grades 6-8.

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