Math Problem Statement

Diketahui ^{2}\log 3 = a dan ^{3}\log 5 = b , nilai dari ^{18}\log 50 = ...

Solution

The problem provided is:

2log3=a and 3log5=b, determine the value of 18log50.^{2}\log 3 = a \text{ and } ^{3}\log 5 = b \text{, determine the value of } ^{18}\log 50.

Let's break this down:

Step 1: Express 18log50^{18}\log 50

We know that:

50=2×5250 = 2 \times 5^2

Using the logarithmic property:

18log50=18log(2×52)^{18}\log 50 = ^{18}\log (2 \times 5^2)

This can be split into two terms using the product rule for logarithms:

18log50=18log2+218log5^{18}\log 50 = ^{18}\log 2 + 2 \cdot ^{18}\log 5

Step 2: Change of base formula

The change of base formula is:

mlogn=lognlogm^{m}\log n = \frac{\log n}{\log m}

For 18log2^{18}\log 2:

18log2=log2log18^{18}\log 2 = \frac{\log 2}{\log 18}

For 18log5^{18}\log 5:

18log5=log5log18^{18}\log 5 = \frac{\log 5}{\log 18}

Step 3: Substituting Known Values

From the question, we know:

  • 2log3=a^{2}\log 3 = a, which means log3log2=a\frac{\log 3}{\log 2} = a.
  • 3log5=b^{3}\log 5 = b, which means log5log3=b\frac{\log 5}{\log 3} = b.

These relationships can be used to compute 18log50^{18}\log 50, but we'd need to know more about 18log3^{18}\log 3 and 18log5^{18}\log 5. Would you like to explore this further?


Here are five follow-up questions to consider:

  1. What logarithmic property can help simplify mlog(a×b)^{m}\log (a \times b)?
  2. How do you apply the change of base formula to other logarithms?
  3. Can we solve 2log3=a^{2}\log 3 = a to find a more precise value for log3\log 3?
  4. What additional information would help solve this problem more efficiently?
  5. How does the change of base formula impact different logarithmic values?

Tip: When working with logarithms, remember that properties like the product rule, quotient rule, and change of base formula are your best tools for simplification.

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Math Problem Analysis

Mathematical Concepts

Logarithms
Change of Base Formula
Logarithmic Properties

Formulas

^{m}\log n = \frac{\log n}{\log m}
^{m}\log (a \times b) = ^{m}\log a + ^{m}\log b

Theorems

Change of Base Theorem
Product Rule for Logarithms

Suitable Grade Level

Grades 10-12