Math Problem Statement

Find an equation of the circle that passes through the points (3, 4),

(−5, −2), and (3, −2). (Suggestion: The equation of a circle can be written as x2 + y2 + ax + by = c.)

Solution

To find the equation of the circle passing through the points (3,4)(3, 4), (5,2)(-5, -2), and (3,2)(3, -2), we start with the general form of the equation of a circle:

x2+y2+ax+by=cx^2 + y^2 + ax + by = c

Step 1: Substituting the points into the equation

For each point, substitute (x,y)(x, y) into the equation to form a system of equations.

  1. Using (3,4)(3, 4): 32+42+3a+4b=c3^2 + 4^2 + 3a + 4b = c 9+16+3a+4b=c3a+4bc=25(Equation 1)9 + 16 + 3a + 4b = c \quad \Rightarrow \quad 3a + 4b - c = -25 \quad \text{(Equation 1)}

  2. Using (5,2)(-5, -2): (5)2+(2)25a2b=c(-5)^2 + (-2)^2 - 5a - 2b = c 25+45a2b=c5a2bc=29(Equation 2)25 + 4 - 5a - 2b = c \quad \Rightarrow \quad -5a - 2b - c = -29 \quad \text{(Equation 2)}

  3. Using (3,2)(3, -2): 32+(2)2+3a2b=c3^2 + (-2)^2 + 3a - 2b = c 9+4+3a2b=c3a2bc=13(Equation 3)9 + 4 + 3a - 2b = c \quad \Rightarrow \quad 3a - 2b - c = -13 \quad \text{(Equation 3)}

Step 2: Solve the system of equations

We now solve for aa, bb, and cc using these equations:

  1. 3a+4bc=253a + 4b - c = -25
  2. 5a2bc=29-5a - 2b - c = -29
  3. 3a2bc=133a - 2b - c = -13

Step 2.1: Eliminate cc

Subtract Equation 3 from Equation 1: (3a+4bc)(3a2bc)=25(13)(3a + 4b - c) - (3a - 2b - c) = -25 - (-13) 6b=12b=26b = -12 \quad \Rightarrow \quad b = -2

Substitute b=2b = -2 into Equation 1 and Equation 2:

  1. From Equation 1: 3a+4(2)c=253a + 4(-2) - c = -25 3a8c=253ac=17(Equation 4)3a - 8 - c = -25 \quad \Rightarrow \quad 3a - c = -17 \quad \text{(Equation 4)}

  2. From Equation 2: 5a2(2)c=29-5a - 2(-2) - c = -29 5a+4c=295ac=33(Equation 5)-5a + 4 - c = -29 \quad \Rightarrow \quad -5a - c = -33 \quad \text{(Equation 5)}

Step 2.2: Solve for aa and cc

Subtract Equation 4 from Equation 5: (5ac)(3ac)=33(17)(-5a - c) - (3a - c) = -33 - (-17) 8a=16a=2-8a = -16 \quad \Rightarrow \quad a = 2

Substitute a=2a = 2 into Equation 4: 3(2)c=173(2) - c = -17 6c=17c=236 - c = -17 \quad \Rightarrow \quad c = 23

Step 3: Write the equation of the circle

Now that we have a=2a = 2, b=2b = -2, and c=23c = 23, the equation of the circle is:

x2+y2+2x2y=23x^2 + y^2 + 2x - 2y = 23

Would you like further explanation or to verify these results step-by-step? Here are five questions to deepen your understanding:

  1. Why do we use the general equation of a circle to solve such problems?
  2. How can the substitution method help solve systems of equations effectively?
  3. What is the significance of each variable (a,b,ca, b, c) in the circle equation?
  4. Could you apply this method to find the equation of a circle with different points?
  5. How would this process change if we used a matrix to solve the system of equations?

Tip: To confirm your circle equation, you can substitute the given points back into the equation and check if they satisfy it.

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Math Problem Analysis

Mathematical Concepts

Geometry
Analytic Geometry
Systems of Equations

Formulas

Equation of a circle: x^2 + y^2 + ax + by = c
Methods for solving systems of linear equations

Theorems

Fundamental properties of a circle in Cartesian coordinates

Suitable Grade Level

Grades 10-12