Math Problem Statement

A new quick test for covid reports a sensitivity of 75% and specificity of 70%. Due to an outbreak of covid, the new quick test was given to all residents of a community and 50 % of the tests came back positive. What is the prevalence of covid in that community?

Solution

To determine the prevalence of COVID-19 in the community, we can apply Bayes' Theorem. The information provided includes the sensitivity, specificity, and the proportion of positive tests.

Let's define the terms:

  • Sensitivity (P(PositiveDisease)P(\text{Positive}|\text{Disease})): 75%
  • Specificity (P(NegativeNo Disease)P(\text{Negative}|\text{No Disease})): 70%
  • Proportion of Positive Tests (P(Positive)P(\text{Positive})): 50% (This is also known as the positive predictive value in some contexts, but here it refers to the total fraction of positive tests.)

The prevalence (P(Disease)P(\text{Disease})) is what we need to find.

Step 1: Define known probabilities

  • P(PositiveDisease)=0.75P(\text{Positive}|\text{Disease}) = 0.75 (Sensitivity)
  • P(NegativeNo Disease)=0.70P(\text{Negative}|\text{No Disease}) = 0.70 (Specificity)
  • P(PositiveNo Disease)=1P(NegativeNo Disease)=10.70=0.30P(\text{Positive}|\text{No Disease}) = 1 - P(\text{Negative}|\text{No Disease}) = 1 - 0.70 = 0.30

Step 2: Use the law of total probability to express P(Positive)P(\text{Positive})

P(Positive)=P(PositiveDisease)P(Disease)+P(PositiveNo Disease)P(No Disease)P(\text{Positive}) = P(\text{Positive}|\text{Disease}) \cdot P(\text{Disease}) + P(\text{Positive}|\text{No Disease}) \cdot P(\text{No Disease})

We know P(Positive)=0.50P(\text{Positive}) = 0.50, so:

0.50=0.75P(Disease)+0.30(1P(Disease))0.50 = 0.75 \cdot P(\text{Disease}) + 0.30 \cdot (1 - P(\text{Disease}))

Step 3: Solve for P(Disease)P(\text{Disease})

Expanding and rearranging the equation:

0.50=0.75P(Disease)+0.300.30P(Disease)0.50 = 0.75 \cdot P(\text{Disease}) + 0.30 - 0.30 \cdot P(\text{Disease}) 0.500.30=0.75P(Disease)0.30P(Disease)0.50 - 0.30 = 0.75 \cdot P(\text{Disease}) - 0.30 \cdot P(\text{Disease}) 0.20=0.45P(Disease)0.20 = 0.45 \cdot P(\text{Disease}) P(Disease)=0.200.450.444P(\text{Disease}) = \frac{0.20}{0.45} \approx 0.444

So, the prevalence of COVID-19 in the community is approximately 44.4%.

Would you like more details on this calculation, or do you have any questions?

Related Questions:

  1. How does increasing the sensitivity of a test affect the prevalence calculation?
  2. What would the prevalence be if the specificity were increased to 80%?
  3. How does the proportion of positive tests (50% in this case) influence the prevalence estimate?
  4. Can you explain how Bayes' Theorem applies in other real-world situations?
  5. What are the implications of a high false-positive rate in mass testing?

Tip:

Remember, sensitivity and specificity are crucial in interpreting test results, especially in scenarios where the disease prevalence is either very high or very low.

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Math Problem Analysis

Mathematical Concepts

Probability
Bayes' Theorem
Epidemiology

Formulas

P(Positive) = P(Positive|Disease) * P(Disease) + P(Positive|No Disease) * P(No Disease)
P(Positive|No Disease) = 1 - Specificity

Theorems

Bayes' Theorem

Suitable Grade Level

Grades 10-12