Math Problem Statement

Now suppose the prevalence of chlamydia infection among patients attending an STD clinic is 40%  

Sensitivity = true pos rate = 80%

  Specificity = true neg rate = 95%

  Question:  What is the probability that someone attending an STD clinic will test positive for chlamydia?

Solution

We are asked to calculate the probability that someone attending an STD clinic will test positive for chlamydia. To solve this, we can use the concept of total probability, which combines the sensitivity (true positive rate), specificity (true negative rate), and the prevalence of the disease (prior probability).

Given Data:

  • Prevalence of chlamydia P(Chlamydia)=0.40P(\text{Chlamydia}) = 0.40
  • Sensitivity (True positive rate) P(Positive Test | Chlamydia)=0.80P(\text{Positive Test | Chlamydia}) = 0.80
  • Specificity (True negative rate) P(Negative Test | No Chlamydia)=0.95P(\text{Negative Test | No Chlamydia}) = 0.95

Step 1: Defining the probabilities

  1. Prevalence of chlamydia: This is the probability that a person attending the clinic has chlamydia, P(Chlamydia)=0.40P(\text{Chlamydia}) = 0.40.

  2. Probability of not having chlamydia: This is P(No Chlamydia)=1P(Chlamydia)=0.60P(\text{No Chlamydia}) = 1 - P(\text{Chlamydia}) = 0.60.

  3. Probability of testing positive given chlamydia: Sensitivity, P(Positive | Chlamydia)=0.80P(\text{Positive | Chlamydia}) = 0.80.

  4. Probability of testing positive given no chlamydia: This is the false positive rate, which is P(Positive | No Chlamydia)=1Specificity=10.95=0.05P(\text{Positive | No Chlamydia}) = 1 - \text{Specificity} = 1 - 0.95 = 0.05.

Step 2: Total probability of testing positive

The probability that someone tests positive for chlamydia can be calculated using the law of total probability:

P(Positive)=P(Positive | Chlamydia)P(Chlamydia)+P(Positive | No Chlamydia)P(No Chlamydia)P(\text{Positive}) = P(\text{Positive | Chlamydia}) \cdot P(\text{Chlamydia}) + P(\text{Positive | No Chlamydia}) \cdot P(\text{No Chlamydia})

Substituting the known values:

P(Positive)=(0.80×0.40)+(0.05×0.60)P(\text{Positive}) = (0.80 \times 0.40) + (0.05 \times 0.60) P(Positive)=0.32+0.03=0.35P(\text{Positive}) = 0.32 + 0.03 = 0.35

Thus, the probability that someone attending the STD clinic will test positive for chlamydia is 35%.


Would you like to explore this further or have more details about this process? Here are some related questions to deepen your understanding:

  1. How does a higher prevalence of chlamydia affect the probability of testing positive?
  2. What is the probability that someone who tests positive actually has chlamydia (positive predictive value)?
  3. How does changing the sensitivity impact the probability of testing positive?
  4. What is the probability that someone tests negative for chlamydia?
  5. How would the false negative rate influence the overall test accuracy?

Tip: Sensitivity and specificity are crucial for understanding the performance of a diagnostic test, but the disease's prevalence plays a significant role in interpreting the results.

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Math Problem Analysis

Mathematical Concepts

Probability
Bayes' Theorem
Total Probability

Formulas

P(Positive) = P(Positive | Chlamydia) * P(Chlamydia) + P(Positive | No Chlamydia) * P(No Chlamydia)
P(No Chlamydia) = 1 - P(Chlamydia)
P(Positive | No Chlamydia) = 1 - Specificity

Theorems

Law of Total Probability

Suitable Grade Level

College Level or Advanced High School (Grades 11-12)