To solve the problem presented in the image, let’s break it down.

The area $A$ of a parallelogram is given by the formula:

$A = \text{base} \times \text{height}$

Given:

• Base = 9 units
• Area = 72 square units

We need to find the height. Rearrange the formula to solve for height:

$\text{Height} = \frac{\text{Area}}{\text{Base}}$

Substitute the given values:

$\text{Height} = \frac{72}{9} = 8 \, \text{units}$

Final Answer:

The height of the parallelogram is 8 units.

Would you like me to explain this further or provide details about parallelograms? Let me know!

Here are 5 related questions to expand your knowledge:

1. What is the formula for the area of a parallelogram in terms of vectors?
2. How would the height change if the base were doubled while keeping the area constant?
3. Can a parallelogram have a height larger than its base? Why or why not?
4. How is the formula for the area of a parallelogram similar to that of a triangle?
5. If the height were given as a fraction, how would we simplify it?

Tip:

Always ensure the base and height are perpendicular to each other when calculating the area of a parallelogram.