A parallelogram has an area of 12 units and a base of 9 units. What is the matching height?

To find the height of a parallelogram, you can use the formula for the area of a parallelogram:

\[
\text{Area} = \text{Base} \times \text{Height}
\]

Given that the area is 12 square units and the base is 9 units, you can substitute these values into the formula:

\[
12 = 9 \times \text{Height}
\]

To solve for the height, divide both sides by 9:

\[
\text{Height} = \frac{12}{9} = \frac{4}{3} \text{ units}
\]

So, the height is \(\frac{4}{3}\) units.

Would you like further details or have any questions?

Here are some related questions you might find interesting:
1. What is the formula for the area of a parallelogram when given two sides and an angle?
2. How would the height change if the area were doubled but the base remained the same?
3. Can the height of a parallelogram be longer than its base?
4. What happens to the area if both the base and height are tripled?
5. How do you find the height of a parallelogram if only the diagonals are known?

**Tip:** Always remember that the height in a parallelogram is the perpendicular distance from the base to the opposite side, not necessarily the side length.

Discover how to calculate the height of a parallelogram with an area of 12 units and a base of 9 units. This problem explores the geometry concept of parallelograms and involves solving a linear equation to find the height. Suitable for students in Grades 6-8.

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