The image shows a parallelogram with a given base of 12 inches, an unknown height $h$, and an area of 72 square inches. To find the height $h$, we can use the formula for the area of a parallelogram:

$\text{Area} = \text{Base} \times \text{Height}$

Given:

• Area = 72 in²
• Base = 12 in

Substitute these values into the formula:

$72 = 12 \times h$

Now, solve for $h$:

$h = \frac{72}{12} = 6 \, \text{inches}$

Thus, the height $h$ is 6 inches.

Would you like any further details or clarifications?

Here are some related questions to explore further:

1. How would you find the height if the base were unknown instead?
2. What is the formula for the area of other quadrilaterals like trapezoids or rectangles?
3. How can you calculate the perimeter of this parallelogram?
4. What are the properties of a parallelogram in terms of angles and sides?
5. Can you derive the formula for the area of a parallelogram using vectors?

Tip: Always remember that in a parallelogram, opposite sides are equal, and opposite angles are equal as well!