A parallelogram has an area of `12` square units and a base of `9` units.

What is the matching height?

The area \( A \) of a parallelogram is given by the formula:

\[
A = \text{base} \times \text{height}
\]

We know the area is 12 square units and the base is 9 units. Let \( h \) represent the height. Substituting the known values into the formula:

\[
12 = 9 \times h
\]

To solve for \( h \), divide both sides by 9:

\[
h = \frac{12}{9} = \frac{4}{3} \text{ units}
\]

Thus, the height of the parallelogram is \( \frac{4}{3} \) units.

Would you like more details or have any further questions?

Here are 5 related questions:
1. How would the area formula change if the parallelogram were rotated?
2. What would the height be if the base were doubled but the area remained the same?
3. How can you derive the formula for the area of a parallelogram using vectors?
4. What happens to the height if both the base and the area are doubled?
5. How is the area of a parallelogram related to the area of a rectangle with the same base and height?

**Tip:** In any parallelogram, the base and height must be perpendicular to each other to calculate the area correctly.

A parallelogram has an area of 12 square units and a base of 9 units. What is the matching height?

Find the height of a parallelogram with an area of 12 square units and a base of 9 units. This problem uses the area formula for parallelograms: A = base × height. Suitable for students in Grades 6-8, this problem emphasizes geometric concepts and basic algebra.

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