The image shows a question about finding the height of a parallelogram. Here's the breakdown:

1. Given Information:

   • The area of the parallelogram is 6 square inches.
   • The base is 5 inches (one side of the parallelogram).
   • The height to be found is perpendicular to the base.
   • The parallelogram is drawn with a side length of 2 inches, but this is not directly relevant for the height calculation.

2. Formula for the area of a parallelogram: $\text{Area} = \text{base} \times \text{height}$ Substituting the known values: $6 = 5 \times h$ To solve for the height $h$, divide both sides by 5: $h = \frac{6}{5} = 1.2 \, \text{inches}$

Answer:

The height of the parallelogram is 1.2 inches.

Would you like a more detailed explanation or have further questions on this problem?

Here are five related questions to expand on this concept:

1. How do you calculate the area of a triangle using height and base?
2. What happens to the area if the base of the parallelogram is doubled but the height remains the same?
3. Can the side length of 2 inches ever be used as a base for this parallelogram?
4. How would you find the perimeter of this parallelogram if all sides were given?
5. How does the formula for the area of a parallelogram differ from that of a rectangle?

Tip: The height of a parallelogram is always perpendicular to the base, no matter the slant of the sides!