The position of a snail, s(t), in centimeters, after t seconds have passed, is measured at 10-second
intervals and recorded in the table below.

t 0 10 20 30 40 50 60
s(t) 6 14 22 36 41 39 36
Find the snail’s average velocity during the first 30 seconds.

The average velocity of the snail during the first 30 seconds can be calculated using the formula for average velocity:

\[
\text{Average Velocity} = \frac{\text{Change in Position}}{\text{Change in Time}}
\]

From the table:
- At \( t = 0 \), \( s(0) = 6 \) cm
- At \( t = 30 \), \( s(30) = 36 \) cm

So, the change in position during the first 30 seconds is:

\[
\Delta s = s(30) - s(0) = 36 - 6 = 30 \text{ cm}
\]

The change in time is:

\[
\Delta t = 30 - 0 = 30 \text{ seconds}
\]

Now, applying the formula:

\[
\text{Average Velocity} = \frac{30 \text{ cm}}{30 \text{ s}} = 1 \text{ cm/s}
\]

So, the snail's average velocity during the first 30 seconds is \( 1 \, \text{cm/s} \).

Would you like more details or have any questions? Here are some related questions:

1. What is the snail’s average velocity between 10 and 40 seconds?
2. How can the average velocity be interpreted in terms of the snail's motion?
3. What is the snail's position at 50 seconds, and how does its velocity change after 30 seconds?
4. How would the average velocity change if the time interval were from 0 to 60 seconds?
5. Can we determine the snail's instantaneous velocity at any specific time from this data?

**Tip:** Average velocity is based on overall displacement, not the total distance traveled!

The position of a snail, s(t), in centimeters, after t seconds have passed, is measured at 10-second intervals and recorded in the table below.

t: 0 10 20 30 40 50 60
s(t): 6 14 22 36 41 39 36

Find the snail’s average velocity during the first 30 seconds.

Learn how to find the average velocity of a snail during the first 30 seconds based on position data. This problem includes concepts of average velocity and linear motion, suitable for students in Grades 6-8.

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