To calculate the average velocity of the object during the time interval from 0 to 2 seconds, we can use the formula for average velocity:

$v_{\text{avg}} = \frac{\Delta x}{\Delta t}$

where:

• $\Delta x$ is the change in position,
• $\Delta t$ is the change in time.

From the graph, at $t = 0 \, \text{s}$, the position $x = 0 \, \text{m}$. At $t = 2 \, \text{s}$, the position $x = 2 \, \text{m}$.

So: $\Delta x = 2 \, \text{m} - 0 \, \text{m} = 2 \, \text{m}$ $\Delta t = 2 \, \text{s} - 0 \, \text{s} = 2 \, \text{s}$

Thus, the average velocity is: $v_{\text{avg}} = \frac{2 \, \text{m}}{2 \, \text{s}} = 1 \, \text{m/s}$

The average velocity of the object during the time interval from 0 seconds to 2 seconds is 1 m/s.

Would you like any further details or have any questions?

Here are five related questions you might find useful:

1. What is the average velocity between 2 seconds and 3 seconds?
2. How can you calculate the instantaneous velocity at $t = 1 \, \text{s}$?
3. What is the total displacement of the object from 0 to 6 seconds?
4. How would you determine the average velocity over the entire 6-second interval?
5. How does the direction of the velocity change over different time intervals?

Tip: The average velocity can be positive or negative depending on the direction of the object's motion.