A group of friends wants to go to the amusement park. They have no more than $295 to spend on parking and admission. Parking is $11.50, and tickets cost $39 per person, including tax. Which inequality can be used to determine xx, the maximum number of people who can go to the amusement park?

We can set up an inequality to model the situation based on the information provided:

- The cost of parking is $11.50 (this is a fixed cost).
- The cost of admission for each person is $39.
- The total amount of money available is no more than $295.

Let $ x $ represent the number of people who can go to the amusement park.

The total cost consists of the parking cost plus the cost for all $ x $ people. Therefore, the inequality can be written as:

\[
11.50 + 39x \leq 295
\]

This inequality can now be solved to determine the maximum value of $ x $.

Would you like me to solve this inequality or give more details on how to solve it?

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Here are 5 related questions to expand on this:

1. How can we solve the inequality to find the maximum number of people who can attend?
2. What happens if the parking cost increases? How does it affect the number of people?
3. What if each person has to pay an additional fee for rides? How would the inequality change?
4. How would the inequality change if the group had a larger budget, say $350?
5. Can we explore how fractional numbers of people (partial tickets) would be treated in such cases?

**Tip:** Always check that fixed costs (like parking) are accounted for separately from per-person costs to avoid mistakes in budgeting.

A group of friends wants to go to the amusement park. They have no more than $295 to spend on parking and admission. Parking is $11.50, and tickets cost $39 per person, including tax. Which inequality can be used to determine x, the maximum number of people who can go to the amusement park?

Learn how to solve a linear inequality to determine the maximum number of people who can attend an amusement park with a budget of $295. Parking costs $11.50, and tickets are $39 per person. This problem covers key algebraic concepts like linear inequalities and budgeting. Suitable for students in Grades 7-10.

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