A group of friends wants to go to the amusement park. They have $416.75 to spend on parking and admission. Parking is $15.25, and tickets cost $36.50 per person, including tax. Which equation could be used to determine xx, the number of people who can go to the amusement park?

To determine the number of people, $ x $, who can go to the amusement park, we need to set up an equation that accounts for the total amount of money available, the parking cost, and the ticket prices for each person.

### Breakdown of Costs:
- Total money available: $416.75
- Parking cost: $15.25 (this is a fixed cost)
- Ticket cost per person: $36.50

The total cost of the trip is the sum of the parking cost and the cost of tickets for $ x $ people. The total ticket cost is $ 36.50x $, where $ x $ is the number of people.

### Equation:
The total amount they can spend is $416.75, and this must cover both parking and the tickets. Therefore, the equation is:

\[
15.25 + 36.50x = 416.75
\]

This equation represents the relationship between the number of people going and the total available money.

Would you like help solving this equation or further details on how to interpret it?

### 5 Related Questions:
1. How many people can go if they only had $350 to spend?
2. What if parking was free—how would that change the equation?
3. What would the equation be if the ticket price increased by $5?
4. If parking increased to $20, what would the new equation be?
5. How many people could go if they had $500 instead?

### Tip:
When setting up equations from word problems, always isolate the fixed costs and variable costs to ensure the structure is clear.

A group of friends wants to go to the amusement park. They have $416.75 to spend on parking and admission. Parking is $15.25, and tickets cost $36.50 per person, including tax. Which equation could be used to determine x, the number of people who can go to the amusement park?

Learn how to set up and solve a real-world linear equation based on an amusement park admission problem. Find out how many friends can attend the park with a budget of $416.75, factoring in parking and ticket costs. Ideal for Grades 6-8 students practicing algebra and word problems.

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