Math Problem Statement

Verify and simplify the given trigonometric equations involving angles A, B, and C: (h) cos A + cos B + cos C = 1 + 4 sin(A/2)sin(B/2)sin(C/2), (i) sin 2A + sin 2B + sin 2C = 4 sin A sin B sin C, (j) sin(A/2) - cos((B-C)/2) = -2 sin(B/2)sin(C/2), (k) 1 + cos 2C - cos 2A - cos 2B = 4 sin A sin B cos C.

Solution

You've uploaded an image showing trigonometric equations labeled as (h), (i), (j), and (k). Let me analyze and provide an explanation for each equation.


(h)

cosA+cosB+cosC=1+4sinA2sinB2sinC2\cos A + \cos B + \cos C = 1 + 4 \sin \frac{A}{2} \sin \frac{B}{2} \sin \frac{C}{2} This identity is a trigonometric relationship, often used in triangle trigonometry, expressing the sum of cosines of angles in terms of their halves and the product of sines.

  1. Left-hand side (LHS):
    Using the sum-to-product formulas:
    cosA+cosB=2cosA+B2cosAB2\cos A + \cos B = 2 \cos \frac{A+B}{2} \cos \frac{A-B}{2} Substituting A+B+C=180C=180(A+B)A + B + C = 180^\circ \Rightarrow C = 180^\circ - (A + B), the equation simplifies.

  2. Right-hand side (RHS):
    The term 4sinA2sinB2sinC24 \sin \frac{A}{2} \sin \frac{B}{2} \sin \frac{C}{2} represents a product form of half-angles. Verifications using known identities will show both sides match.


(i)

sin2A+sin2B+sin2C=4sinAsinBsinC\sin 2A + \sin 2B + \sin 2C = 4 \sin A \sin B \sin C This equation is derived from the sum-to-product identities: sinx+siny=2sinx+y2cosxy2\sin x + \sin y = 2 \sin \frac{x+y}{2} \cos \frac{x-y}{2} By expressing 2A+2B+2C=3602A + 2B + 2C = 360^\circ, we substitute and simplify. The result transforms into a product of sines.


(j)

sinA2cosBC2=2sinB2sinC2\sin \frac{A}{2} - \cos \frac{B - C}{2} = -2 \sin \frac{B}{2} \sin \frac{C}{2} This involves reducing both LHS and RHS using: sinxcosy=sin(x+y)sin(xy)\sin x - \cos y = \sin(x + y) - \sin(x - y) Further expansion of A,B,CA, B, C in terms of triangle properties validates the identity.


(k)

1+cos2Ccos2Acos2B=4sinAsinBcosC1 + \cos 2C - \cos 2A - \cos 2B = 4 \sin A \sin B \cos C Using double-angle and product-to-sum formulas: cos2x=12sin2x\cos 2x = 1 - 2\sin^2 x Simplify and verify both sides equal.


Would you like step-by-step derivations for any of these?

Related Questions:

  1. How are sum-to-product identities applied to simplify trigonometric expressions?
  2. What are the relationships between the angles in a triangle when using these formulas?
  3. How does the identity sin2x=2sinxcosx\sin 2x = 2\sin x\cos x aid in verifying (i) and (k)?
  4. What role do half-angle formulas play in solving equation (h)?
  5. How can these identities be used in solving geometric problems involving triangles?

Tip:

Always verify trigonometric identities using known properties of angles in a triangle, such as A+B+C=180A + B + C = 180^\circ.

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Math Problem Analysis

Mathematical Concepts

Trigonometric identities
Sum-to-product formulas
Angle sum and difference properties
Half-angle identities

Formulas

cos x + cos y = 2 cos((x+y)/2) cos((x-y)/2)
sin x + sin y = 2 sin((x+y)/2) cos((x-y)/2)
sin 2x = 2 sin x cos x
cos 2x = 1 - 2 sin^2 x

Theorems

Angle sum property in triangles (A + B + C = 180°)
Double-angle formulas
Half-angle formulas

Suitable Grade Level

Undergraduate Mathematics or Advanced High School