Good question! Let's break down how we simplified \(\sqrt{56}\):

### Step 1: Prime Factorization
First, we find the prime factors of 56:
\[
56 = 2 \times 28
\]
\[
28 = 2 \times 14
\]
\[
14 = 2 \times 7
\]
So, the prime factorization of 56 is:
\[
56 = 2 \times 2 \times 2 \times 7
\]

### Step 2: Grouping Factors
Now, we look for pairs of factors under the square root:
\[
\sqrt{56} = \sqrt{2 \times 2 \times 14} = \sqrt{4 \times 14}
\]

### Step 3: Simplify the Square Root
We know that \(\sqrt{4} = 2\), so:
\[
\sqrt{56} = \sqrt{4 \times 14} = 2\sqrt{14}
\]

That's where the \(4 \times 14\) comes from. It helps simplify the square root to \(2\sqrt{14}\).

Would you like to ask more questions or need further clarification?

Here are some related questions:
1. How do you perform prime factorization of a number?
2. Why is it useful to simplify square roots in equations?
3. How do you simplify other square roots, like \(\sqrt{72}\) or \(\sqrt{18}\)?
4. What are other methods to solve quadratic equations besides the quadratic formula?
5. Can all square roots be simplified? Why or why not?

**Tip:** When simplifying square roots, always look for the largest perfect square factor to make your work easier.

Explore the solution to the problem: What is 4 times 14? Learn about arithmetic operations and multiplication. Suitable for students in Grades 4-6.

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