Math Problem Statement

solve 15 please

Triangle ABC with vertices A(-2, -2), B(-3, 1), and C(1, 1) is translated by (x, y) → (x - 1, y + 3). Then the image, triangle A'B'C', is translated by (x, y) → (x + 4, y - 1), resulting in triangle A''B''C''. Find the coordinates for the vertices of triangle A''B''C'' and write a rule for the translation that maps triangle ABC to triangle A''B''C''.

Solution

The problem describes a series of translations for triangle ABCABC with vertices A(2,2)A(-2, -2), B(3,1)B(-3, 1), and C(1,1)C(1, 1). The translations occur in two steps:

  1. The first translation moves the points by (x,y)(x1,y+3)(x, y) \to (x - 1, y + 3), producing triangle ABCA'B'C'.
  2. The second translation moves triangle ABCA'B'C' by (x,y)(x+4,y1)(x, y) \to (x + 4, y - 1), producing triangle ABCA''B''C''.

Part (a): Find the coordinates for the vertices of triangle ABCA''B''C''.

  1. First translation (for triangle ABCA'B'C'):

    • For vertex A(2,2)A(-2, -2): (2,2)(21,2+3)=(3,1)(-2, -2) \to (-2 - 1, -2 + 3) = (-3, 1)
    • For vertex B(3,1)B(-3, 1): (3,1)(31,1+3)=(4,4)(-3, 1) \to (-3 - 1, 1 + 3) = (-4, 4)
    • For vertex C(1,1)C(1, 1): (1,1)(11,1+3)=(0,4)(1, 1) \to (1 - 1, 1 + 3) = (0, 4)

    So, after the first translation, the vertices of triangle ABCA'B'C' are: A(3,1),B(4,4),C(0,4)A'(-3, 1), B'(-4, 4), C'(0, 4)

  2. Second translation (for triangle ABCA''B''C''):

    • For vertex A(3,1)A'(-3, 1): (3,1)(3+4,11)=(1,0)(-3, 1) \to (-3 + 4, 1 - 1) = (1, 0)
    • For vertex B(4,4)B'(-4, 4): (4,4)(4+4,41)=(0,3)(-4, 4) \to (-4 + 4, 4 - 1) = (0, 3)
    • For vertex C(0,4)C'(0, 4): (0,4)(0+4,41)=(4,3)(0, 4) \to (0 + 4, 4 - 1) = (4, 3)

    So, the vertices of triangle ABCA''B''C'' are: A(1,0),B(0,3),C(4,3)A''(1, 0), B''(0, 3), C''(4, 3)

Part (b): Write a rule for one translation that maps triangle ABCABC to triangle ABCA''B''C''.

Instead of performing two translations separately, we can combine them into one:

  1. The first translation is (x,y)(x1,y+3)(x, y) \to (x - 1, y + 3).
  2. The second translation is (x,y)(x+4,y1)(x, y) \to (x + 4, y - 1).

We can combine these transformations as follows: (x,y)((x1)+4,(y+3)1)=(x+3,y+2)(x, y) \to ((x - 1) + 4, (y + 3) - 1) = (x + 3, y + 2)

So, the combined translation that maps triangle ABCABC directly to triangle ABCA''B''C'' is: (x,y)(x+3,y+2)(x, y) \to (x + 3, y + 2)


Do you want more details or have any other questions? Here are some related questions:

  1. What would happen if you only apply the second translation to triangle ABCABC?
  2. Can you reverse the process to find the original triangle from ABCA''B''C''?
  3. How can you describe the translations in vector form?
  4. What would the vertices of triangle ABCA'B'C' be if the first translation was different?
  5. How do these translations affect the area and orientation of the triangle?

Tip: When combining multiple transformations, always apply one transformation at a time and simplify the overall movement into a single translation if possible.

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Math Problem Analysis

Mathematical Concepts

Geometry
Translations in the Coordinate Plane

Formulas

(x, y) → (x - 1, y + 3) (Translation 1)
(x, y) → (x + 4, y - 1) (Translation 2)
Combined translation: (x, y) → (x + 3, y + 2)

Theorems

Coordinate Geometry Translation Theorem

Suitable Grade Level

Grades 8-10