Math Problem Statement

Solve the following mathematical problems: 1. (-1)^9 + (1/2)^(-1), 2. [2/3]^-2, 3. (2^4)^2 * (1/2)^(-2), 4. 81^(1/4) - 125^(1/3) + 4^(3/2), 5. 0^5 + (-3)^0

Solution

I see you've uploaded an image with five mathematical questions. Let me help you solve them one by one:

  1. Hasil dari (-1)^9 + (1/2)^(-1) = ...

    • (1)9=1(-1)^9 = -1 because the exponent is odd.
    • (1/2)1=2(1/2)^{-1} = 2 because taking the reciprocal of 1/21/2 gives 2.
    • Therefore, (1)9+(1/2)1=1+2=1(-1)^9 + (1/2)^{-1} = -1 + 2 = 1.

    Answer: 1

  2. Hasil dari [23]2\left[\frac{2}{3}\right]^{-2} adalah = ...

    • (23)2\left(\frac{2}{3}\right)^{-2} means the reciprocal squared.
    • Reciprocal of 23\frac{2}{3} is 32\frac{3}{2}, and squaring it gives 94\frac{9}{4}.

    Answer: 94\frac{9}{4}

  3. Bentuk sederhana dari ((2^4)^2 \times \left(\frac{1}{2}\right)^{-2} = ...

    • (24)2=28(2^4)^2 = 2^{8}.
    • (12)2=22\left(\frac{1}{2}\right)^{-2} = 2^2 because of the negative exponent.
    • Therefore, 28×22=210=10242^8 \times 2^2 = 2^{10} = 1024.

    Answer: 1024

  4. Hasil dari (81^{\frac{1}{4}} - 125^{\frac{1}{3}} + 4^{\frac{3}{2}} = ...

    • 8114=814=381^{\frac{1}{4}} = \sqrt[4]{81} = 3.
    • 12513=1253=5125^{\frac{1}{3}} = \sqrt[3]{125} = 5.
    • 432=43=23=84^{\frac{3}{2}} = \sqrt{4}^3 = 2^3 = 8.
    • Therefore, 35+8=63 - 5 + 8 = 6.

    Answer: 6

  5. Hasil dari (0^5 + (-3)^0 = ...

    • 05=00^5 = 0 because any number raised to a power is 0.
    • (3)0=1(-3)^0 = 1 because any number raised to 0 is 1.
    • Therefore, 0+1=10 + 1 = 1.

    Answer: 1


Would you like further clarification or a breakdown of any of the steps? Here are five related questions for practice:

  1. What is the value of (2)3+(4/5)1(-2)^3 + (4/5)^{-1}?
  2. Simplify (3/4)3(3/4)^{-3}.
  3. Evaluate (53)2×(1/3)3(5^3)^2 \times (1/3)^{-3}.
  4. Find the result of 161/2641/3+93/216^{1/2} - 64^{1/3} + 9^{3/2}.
  5. What is the sum of 20+(1)02^0 + (-1)^0?

Tip: When working with exponents, always remember that negative exponents indicate a reciprocal, and fractional exponents relate to roots!

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Math Problem Analysis

Mathematical Concepts

Exponents
Fractional Powers
Negative Exponents
Basic Arithmetic

Formulas

a^n = a * a * ... * a (n times)
(a/b)^-n = (b/a)^n
a^0 = 1
a^(-n) = 1/a^n
n-th root of a

Theorems

Laws of Exponents
Properties of Powers and Roots
Zero Exponent Rule

Suitable Grade Level

Grades 9-12