Math Problem Statement

By what number should (-2/3)^-3 be divided so that the quotient is (9/8)^-2? The number 144 is multiplied with 2^-3, 12^-1, and 3^-2 consecutively. Find the final product. The product of (3/4)^-4 and (-2/3)^2 is divided by a number so that the quotient is (3/5)^-2. Find the number.

Solution

Let's go through the questions one by one and solve them.

Problem 6:

We need to find a number xx such that:

(23)3x=(98)2\frac{\left( -\frac{2}{3} \right)^{-3}}{x} = \left( \frac{9}{8} \right)^{-2}

Steps:

  1. Simplify both sides. (23)3=(32)3=278\left( -\frac{2}{3} \right)^{-3} = \left( -\frac{3}{2} \right)^3 = -\frac{27}{8} And: (98)2=(89)2=6481\left( \frac{9}{8} \right)^{-2} = \left( \frac{8}{9} \right)^2 = \frac{64}{81}

  2. Now substitute into the equation: 278x=6481\frac{-\frac{27}{8}}{x} = \frac{64}{81}

  3. Solve for xx: x=2786481=278×8164=2187512x = \frac{-\frac{27}{8}}{\frac{64}{81}} = -\frac{27}{8} \times \frac{81}{64} = -\frac{2187}{512}

Thus, the number xx is 2187512-\frac{2187}{512}.


Problem 7:

We are asked to find the product of 144 multiplied by 232^{-3}, 12112^{-1}, and 323^{-2}.

Steps:

  1. Start with 144.
  2. Multiply by 232^{-3}, which is 123=18\frac{1}{2^3} = \frac{1}{8}.
  3. Multiply by 12112^{-1}, which is 112\frac{1}{12}.
  4. Multiply by 323^{-2}, which is 132=19\frac{1}{3^2} = \frac{1}{9}.

Now compute: 144×18×112×19=1448×12×9=144864=16144 \times \frac{1}{8} \times \frac{1}{12} \times \frac{1}{9} = \frac{144}{8 \times 12 \times 9} = \frac{144}{864} = \frac{1}{6}

Thus, the final product is 16\frac{1}{6}.


Problem 8:

We need to find the number yy such that:

(34)4×(23)2y=(35)2\frac{\left( \frac{3}{4} \right)^{-4} \times \left( -\frac{2}{3} \right)^2}{y} = \left( \frac{3}{5} \right)^{-2}

Steps:

  1. Simplify the expressions. (34)4=(43)4=25681\left( \frac{3}{4} \right)^{-4} = \left( \frac{4}{3} \right)^4 = \frac{256}{81} (23)2=49\left( -\frac{2}{3} \right)^2 = \frac{4}{9} So the product is: 25681×49=1024729\frac{256}{81} \times \frac{4}{9} = \frac{1024}{729} On the right-hand side: (35)2=(53)2=259\left( \frac{3}{5} \right)^{-2} = \left( \frac{5}{3} \right)^2 = \frac{25}{9}

  2. Substitute into the equation: 1024729y=259\frac{\frac{1024}{729}}{y} = \frac{25}{9}

  3. Solve for yy: y=1024729259=1024729×925=921618225y = \frac{\frac{1024}{729}}{\frac{25}{9}} = \frac{1024}{729} \times \frac{9}{25} = \frac{9216}{18225}

Thus, the number yy is 921618225\frac{9216}{18225}.


Let me know if you need further details or have any questions! Here are some related questions:

  1. What is the general rule for negative exponents?
  2. How do you simplify fractions raised to a negative power?
  3. How do you handle division of fractions?
  4. Can you explain the reciprocal relationship in fraction exponents?
  5. How does raising a negative fraction to an even power affect the result?

Tip: When working with exponents and fractions, simplifying both the base and exponent first can make the calculations easier!

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Math Problem Analysis

Mathematical Concepts

Exponents
Fractional Powers
Multiplication of Fractions
Division of Fractions

Formulas

a^-n = 1/a^n
(a/b)^n = a^n / b^n
Multiplication of fractions: (a/b) * (c/d) = (a*c)/(b*d)
Division of fractions: (a/b) ÷ (c/d) = (a/b) * (d/c)

Theorems

Rules of Exponents
Properties of Negative Exponents

Suitable Grade Level

Grades 9-12