Find the missing value in each pair of equivalent fractions.

2/5 = 26/x

5/7 = 120/x

Let's solve each pair of equivalent fractions.

### 1. \( \frac{2}{5} = \frac{26}{x} \)

We can solve for \( x \) by cross-multiplying:

\[
2 \cdot x = 5 \cdot 26
\]

\[
2x = 130
\]

Now, divide both sides by 2 to solve for \( x \):

\[
x = \frac{130}{2} = 65
\]

So, the missing value in the first pair is \( x = 65 \).

### 2. \( \frac{5}{7} = \frac{120}{x} \)

Similarly, cross-multiply:

\[
5 \cdot x = 7 \cdot 120
\]

\[
5x = 840
\]

Now, divide both sides by 5:

\[
x = \frac{840}{5} = 168
\]

So, the missing value in the second pair is \( x = 168 \).

### Final Answers:
1. \( x = 65 \)
2. \( x = 168 \)

Would you like a detailed explanation or have any questions?

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Here are 5 related questions:
1. How do you solve proportions using cross-multiplication?
2. What are equivalent fractions and how are they identified?
3. How can you simplify a fraction to its lowest terms?
4. What is the process of converting improper fractions to mixed numbers?
5. How do you add or subtract fractions with different denominators?

**Tip:** When solving proportions, cross-multiplication is a quick and effective way to find the unknown value.

Find the missing value in each pair of equivalent fractions. 2/5 = 26/x and 5/7 = 120/x

Learn how to solve equivalent fractions using cross-multiplication in the problem 2/5 = 26/x and 5/7 = 120/x. This solution walks through finding the missing values with step-by-step explanations. Ideal for Grades 6-8 students studying proportions.

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