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The problem requires replacing the boxes with the correct numbers to maintain equivalence between fractions. Let's solve each part step-by-step:

### (a) \(\frac{2}{7} = \frac{8}{\square}\)
To find the missing number, apply cross-multiplication:
\[
2 \times \square = 7 \times 8
\]
\[
2 \times \square = 56 \quad \Rightarrow \quad \square = \frac{56}{2} = 28
\]
So, the missing number is **28**.

### (b) \(\frac{5}{8} = \frac{10}{\square}\)
Using cross-multiplication again:
\[
5 \times \square = 8 \times 10
\]
\[
5 \times \square = 80 \quad \Rightarrow \quad \square = \frac{80}{5} = 16
\]
So, the missing number is **16**.

### (c) \(\frac{3}{5} = \frac{\square}{20}\)
Cross-multiplication gives:
\[
3 \times 20 = 5 \times \square
\]
\[
60 = 5 \times \square \quad \Rightarrow \quad \square = \frac{60}{5} = 12
\]
So, the missing number is **12**.

### (d) \(\frac{45}{60} = \frac{15}{\square}\)
Cross-multiply:
\[
45 \times \square = 60 \times 15
\]
\[
45 \times \square = 900 \quad \Rightarrow \quad \square = \frac{900}{45} = 20
\]
So, the missing number is **20**.

### (e) \(\frac{18}{24} = \frac{\square}{4}\)
Cross-multiplication yields:
\[
18 \times 4 = 24 \times \square
\]
\[
72 = 24 \times \square \quad \Rightarrow \quad \square = \frac{72}{24} = 3
\]
So, the missing number is **3**.

### Final answers:
- (a) 28
- (b) 16
- (c) 12
- (d) 20
- (e) 3

Would you like any additional details or explanations?

Here are 5 related questions for practice:
1. What is the method of cross-multiplication, and how does it help in solving fraction equivalence?
2. How do you find equivalent fractions for any given fraction?
3. Can two fractions be equivalent if their numerators and denominators are not multiples of each other?
4. How can you simplify a fraction to find its simplest form?
5. What is the relationship between fractions and ratios?

**Tip:** Cross-multiplication is a quick way to check if two fractions are equal by multiplying the numerator of one with the denominator of the other.

Replace the boxes in each of the following by the correct number to maintain fraction equivalence.

Learn how to solve fraction equivalence problems by replacing the missing values using cross-multiplication. This detailed solution explains how to apply the formula and maintain proportionality. Suitable for students in Grades 5-7.

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