https://file.aiquickdraw.com/mathbot/file/1726726481032im1iu3vq.jpg

The image shows a sequence of equivalent fractions, where some values are missing. Let's solve for the unknowns step by step.

We are given:

\[
\frac{3}{5} = \frac{\text{?}}{25} = \frac{9}{\text{?}} = \frac{\text{?}}{40}
\]

### 1. Solving for \(\frac{\text{?}}{25}\)

We know that:

\[
\frac{3}{5} = \frac{\text{?}}{25}
\]

To find the missing numerator, we can use cross-multiplication:

\[
3 \times 25 = 5 \times \text{?}
\]

This simplifies to:

\[
75 = 5 \times \text{?}
\]

Now divide both sides by 5:

\[
\text{?} = \frac{75}{5} = 15
\]

So:

\[
\frac{3}{5} = \frac{15}{25}
\]

### 2. Solving for \(\frac{9}{\text{?}}\)

We now know that:

\[
\frac{15}{25} = \frac{9}{\text{?}}
\]

Cross-multiply again:

\[
15 \times \text{?} = 9 \times 25
\]

This simplifies to:

\[
15 \times \text{?} = 225
\]

Now divide both sides by 15:

\[
\text{?} = \frac{225}{15} = 15
\]

So:

\[
\frac{9}{15}
\]

### 3. Solving for \(\frac{\text{?}}{40}\)

We also know:

\[
\frac{9}{15} = \frac{\text{?}}{40}
\]

Using cross-multiplication:

\[
9 \times 40 = 15 \times \text{?}
\]

This simplifies to:

\[
360 = 15 \times \text{?}
\]

Now divide both sides by 15:

\[
\text{?} = \frac{360}{15} = 24
\]

So:

\[
\frac{9}{15} = \frac{24}{40}
\]

### Final Answer:

\[
\frac{3}{5} = \frac{15}{25} = \frac{9}{15} = \frac{24}{40}
\]

Would you like any further explanation or details?

### Related Questions:
1. How do you verify if two fractions are equivalent?
2. Can you simplify the fraction \(\frac{24}{40}\)?
3. What is the least common denominator of 5, 25, 15, and 40?
4. How can you use proportions to solve real-world problems?
5. How do you convert a fraction to a percentage?

### Tip:
Cross-multiplication is a powerful method for comparing and solving equations with fractions.

What are the missing values in the equivalent fractions sequence: 3/5 = ?/25 = 9/? = ?/40?

Learn how to find the missing values in the sequence of equivalent fractions: 3/5 = ?/25 = 9/? = ?/40. This detailed solution uses cross multiplication to solve for unknown numerators and denominators, covering fundamental concepts of fractions and proportions. Ideal for students in Grades 5-7.

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