To find $g(f(-1))$, we'll follow these steps:

1. Find $f(-1)$: Given $f(x) = 4x + 3$, substitute $x = -1$ into $f(x)$: $f(-1) = 4(-1) + 3 = -4 + 3 = -1$ So, $f(-1) = -1$.

2. Find $g(f(-1)) = g(-1)$: Now, using $g(x) = x - 2$, substitute $x = -1$ into $g(x)$: $g(-1) = -1 - 2 = -3$

Thus, $g(f(-1)) = -3$.

Would you like more details or have any questions?

Here are 5 related questions:

1. What is $g(f(x))$ in terms of $x$?
2. Find $f(g(2))$ given the same functions.
3. If $f(x) = 4x + 3$ and $g(x) = x^2 - 2$, what is $g(f(1))$?
4. Find $g(f(x))$ when $f(x) = 2x + 1$ and $g(x) = 3x - 5$.
5. What is the inverse function of $f(x) = 4x + 3$?

Tip: In composite functions, always work from the innermost function to the outermost function.