To solve $g(f(2))$ where:

• $f(x) = 4x + 3$
• $g(x) = x - 7$

Step 1: Find $f(2)$

$f(2) = 4(2) + 3 = 8 + 3 = 11$

Step 2: Now substitute $f(2) = 11$ into $g(x)$

$g(f(2)) = g(11) = 11 - 7 = 4$

So, $g(f(2)) = 4$.

Would you like further explanation or have any questions?

Here are some related problems to practice:

1. Find $g(f(3))$ given $f(x) = 4x + 3$ and $g(x) = x - 7$.
2. If $h(x) = 2x + 1$, what is $h(g(f(2)))$?
3. Solve $f(f(2))$ for $f(x) = 4x + 3$.
4. What is $g(g(f(1)))$ given the same functions?
5. Find $g(f(x))$ in terms of $x$.

Tip: Always start by simplifying the inner function before applying the outer function.