
The cost for a pool membership for a family at a community pool is $250 plus $370 per month. A family paid a total of $1,360. How many months did the family use the pool?

The total cost for the family to use the pool can be modeled by the equation:

\[
\text{Total Cost} = 250 + 370 \times m
\]

where:
- $250$ is the initial membership cost,
- $370$ is the monthly fee,
- $m$ is the number of months the family used the pool,
- and the total amount paid is $1,360.

We need to find $m$, so let's set up the equation:

\[
1360 = 250 + 370 \times m
\]

Now, solve for $m$:

1. Subtract 250 from both sides:

\[
1360 - 250 = 370 \times m
\]

\[
1110 = 370 \times m
\]

2. Divide both sides by 370:

\[
m = \frac{1110}{370}
\]

\[
m = 3
\]

Thus, the family used the pool for 3 months.

Would you like more details or have any questions about the process?

Here are 5 related questions for further exploration:
1. What would the total cost be if the family used the pool for 6 months?
2. How much would a family save if the monthly fee was reduced to $300 per month?
3. If another pool charges a $200 membership fee and $400 per month, how long would it take to surpass $1,360 in costs?
4. What if the monthly fee increased to $400 per month; how would that affect the number of months used for a $1,360 total?
5. Can you graph the total cost as a function of the number of months used?

**Tip:** In problems involving both fixed costs and variable costs, break the problem into parts to isolate each variable for easier solving.

The cost for a pool membership for a family at a community pool is $250 plus $370 per month. A family paid a total of $1,360. How many months did the family use the pool?

Find out how to solve a linear equation for the cost of a pool membership. This problem involves determining how many months a family used the pool by solving a basic algebraic equation. Perfect for students in Grades 6-8.

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