To solve the equation \( ax + 2y = 16 \) for \( y \), we need to isolate \( y \) on one side of the equation. Here's how:

### Step-by-step solution:
1. Start with the given equation:
   \[
   ax + 2y = 16
   \]
2. Subtract \( ax \) from both sides to get:
   \[
   2y = 16 - ax
   \]
3. Divide both sides by 2 to solve for \( y \):
   \[
   y = \frac{16 - ax}{2}
   \]

Thus, the solution for \( y \) is:
\[
y = \frac{16 - ax}{2}
\]

Would you like more details or have any questions?

Here are 5 related questions:
1. How does changing the value of \( a \) affect the solution for \( y \)?
2. Can this equation be graphed? What would its graph look like?
3. How would you solve the equation if it were \( ax + 2y = 0 \)?
4. What happens to the solution for \( y \) when \( x = 0 \)?
5. How can this result be used in a system of equations?

**Tip:** Always perform inverse operations to isolate the variable you're solving for.

Discover how to solve the linear equation ax + 2y = 16 for y in this detailed, step-by-step solution. This problem covers fundamental algebraic concepts, including inverse operations and linear equations, suitable for students in Grades 8-10.

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