The given equation is:

$4y - 2x = 16$

We can rewrite this equation in different forms or solve for one variable in terms of the other. Let's isolate $y$ to express the equation in slope-intercept form $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept.

Solving for $y$:

$4y = 2x + 16 \quad (\text{adding } 2x \text{ to both sides})$

$y = \frac{2x + 16}{4} \quad (\text{dividing both sides by } 4)$

$y = \frac{2x}{4} + \frac{16}{4}$

$y = \frac{1}{2}x + 4$

So, the equation in slope-intercept form is:

$y = \frac{1}{2}x + 4$

This means the slope $m = \frac{1}{2}$ and the y-intercept $b = 4$.

Would you like more details or have any other questions?

5 Related Questions:

1. How do you graph a linear equation like $y = \frac{1}{2}x + 4$?
2. What is the slope of a line and how is it interpreted?
3. How do you find the x-intercept of the equation $4y - 2x = 16$?
4. What are parallel and perpendicular lines based on slope?
5. How do you convert an equation into standard form?

Tip: To find the x-intercept of any linear equation, set $y = 0$ and solve for $x$.