Math Problem Statement

Point J is between H and K on line segment HK. Use the given information to solve for x. Also find the length of line segment JK.

HK = 20 HJ = 2x-2 JK = 7x+4

Solution

To solve for xx and find the length of line segment JKJK, we can use the given information:

  • HK=20HK = 20
  • HJ=2x2HJ = 2x - 2
  • JK=7x+4JK = 7x + 4

Since point JJ is between HH and KK, the lengths of HJHJ and JKJK should add up to the total length of HKHK. Therefore, we can write the equation:

HJ+JK=HKHJ + JK = HK

Substituting the given expressions:

(2x2)+(7x+4)=20(2x - 2) + (7x + 4) = 20

Now, let's solve this equation for xx.

Simplify the equation:

2x2+7x+4=202x - 2 + 7x + 4 = 20

Combine like terms:

9x+2=209x + 2 = 20

Subtract 2 from both sides:

9x=189x = 18

Divide by 9:

x=2x = 2

Now that we have x=2x = 2, we can find the length of JKJK:

JK=7x+4=7(2)+4=14+4=18JK = 7x + 4 = 7(2) + 4 = 14 + 4 = 18

Therefore, the length of line segment JKJK is 18 units.

Would you like more details or have any questions? Here are some related questions to explore further:

  1. What is the length of line segment HJHJ with the solved value of xx?
  2. If JJ were to be exactly halfway between HH and KK, how would xx change?
  3. Can you find the coordinates of point JJ if HH is at the origin?
  4. How would the equation change if HKHK was not a straight line but a curve?
  5. What would the equation be if JJ was outside the segment HKHK?

Tip: Always check your substituted values to verify the solution, ensuring there are no calculation errors.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Geometry

Formulas

HJ + JK = HK
2x - 2 + 7x + 4 = 20

Theorems

Segment Addition Postulate

Suitable Grade Level

Grades 8-10