Math Problem Statement

Point J is between H and K on line segment HK. Use the given information to solve for x. Also find the length of line segment JK.

HK = 26 HJ = 7x-2 JK = 3x+8

x = JK=

Solution

We are given the following information about the line segment HKHK with point JJ between HH and KK:

  • HK=26HK = 26
  • HJ=7x2HJ = 7x - 2
  • JK=3x+8JK = 3x + 8

Since JJ is between HH and KK, we can express HKHK as the sum of the lengths of HJHJ and JKJK: HK=HJ+JKHK = HJ + JK Substituting the given expressions: 26=(7x2)+(3x+8)26 = (7x - 2) + (3x + 8) Now, combine like terms: 26=7x2+3x+826 = 7x - 2 + 3x + 8 26=10x+626 = 10x + 6 Next, solve for xx: 266=10x26 - 6 = 10x 20=10x20 = 10x x=2x = 2

Now that we have x=2x = 2, we can substitute this value into the expression for JKJK to find its length: JK=3x+8=3(2)+8=6+8=14JK = 3x + 8 = 3(2) + 8 = 6 + 8 = 14

Thus, the solutions are: x=2x = 2 JK=14JK = 14

Would you like more details on any step or do you have any questions?

Here are 5 related questions to expand on this problem:

  1. What if JKJK was a different function of xx? How would it affect the solution?
  2. How would you solve the problem if HJHJ were expressed in terms of a different variable?
  3. What is the length of HJHJ when x=2x = 2?
  4. How would the solution change if JJ were not exactly between HH and KK?
  5. Can you verify that the sum of HJHJ and JKJK equals HKHK with the calculated values?

Tip: Always check the sum of the segments after solving for xx to ensure the solution satisfies the original equation!

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Geometry - Line Segments

Formulas

Sum of segments: HK = HJ + JK

Theorems

Segment Addition Postulate

Suitable Grade Level

Grades 7-9