To solve the expression \( 12(1+w)u \) when \( w = 4 \) and \( u = 2 \):

1. Substitute \( w = 4 \) into the expression:
   \[
   12(1+4)u
   \]

2. Simplify inside the parentheses:
   \[
   12(5)u
   \]

3. Substitute \( u = 2 \) into the expression:
   \[
   12(5)(2)
   \]

4. Multiply the numbers:
   \[
   12 \times 5 \times 2 = 120
   \]

So, the value of the expression is **120**.

Would you like more details or have any questions? Here are 5 related questions for further practice:

1. What is the value of \( 15(2 + w)u \) when \( w = 3 \) and \( u = 4 \)?
2. Simplify the expression \( 8(3 + w)u \) when \( w = 5 \) and \( u = 2 \).
3. Solve \( 20(1 + w)v \) when \( w = 4 \) and \( v = 3 \).
4. What happens to the expression \( 12(1+w)u \) if \( w = 4 \) and \( u = 3 \)?
5. Evaluate \( 10(2 + w)u \) when \( w = 1 \) and \( u = 6 \).

**Tip:** Always perform operations inside the parentheses first before applying multiplication.

Learn how to solve the expression 12(1+w)u with w=4, u=2 step-by-step. This problem involves arithmetic operations and substitution. Suitable for Grades 7-9 students.

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