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Solve this problem for class 9 students level. Here the whole terms within braces is the power of 25 

The given expression is:

\[
25^{\left(\frac{1}{2} + \log_1^5 27 + \log_{25} 81 \right)}
\]

Let's break it down step by step for a Class 9 level.

### Step 1: Simplify the logarithms

1. **First term:** \(\frac{1}{2}\) remains as is.

2. **Second term:** 
   \[
   \log_1^5 27 = \log_{10} 27
   \]
   Since the logarithm with a subscript \(1^5\) would actually be \(\log_{10} 27\), which can be estimated but isn't necessary for now.

3. **Third term:**
   \[
   \log_{25} 81 = \frac{\log 81}{\log 25}
   \]
  
 Check th

Solve the following expression: 25^{\left(\frac{1}{2} + \log_1^5 27 + \log_{25} 81 \right)}.

This guide explains how to solve the exponential expression 25^{\left(\frac{1}{2} + \log_1^5 27 + \log_{25} 81 \right)}. The problem involves logarithms, change of base formulas, and simplifying exponents. Suitable for students in Grades 8-10.

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