To solve the given expression, we need to evaluate:

$4^{\log 25} \cdot 5^{\log 36} - 2^{\log 9}$

Let's break down each term step-by-step:

Step-by-Step Evaluation:

1. Evaluate $4^{\log 25}$: $4 = 2^2 \quad \text{and} \quad 25 = 5^2$ So: $4^{\log 25} = (2^2)^{\log (5^2)} = 2^{2 \cdot \log (5^2)} = 2^{2 \cdot 2 \log 5} = 2^{4 \log 5} = (2^{\log 5})^4$ Since $2^{\log 5} = 5$, we have: $(2^{\log 5})^4 = 5^4 = 625$

2. Evaluate $5^{\log 36}$: $36 = 6^2 = (2 \cdot 3)^2 = 2^2 \cdot 3^2$ $\log 36 = \log (2^2 \cdot 3^2) = 2 \log 2 + 2 \log 3 = 2 (\log 2 + \log 3)$ Therefore: $5^{\log 36} = 5^{2 (\log 2 + \log 3)} = (5^{\log 2 + \log 3})^2 = (5^{\log 2} \cdot 5^{\log 3})^2 = (2 \cdot 3)^2 = 6^2 = 36$

3. Multiply the two results: $4^{\log 25} \cdot 5^{\log 36} = 625 \cdot 36$ $625 \cdot 36 = 22500$

4. Evaluate $2^{\log 9}$: $9 = 3^2 \implies \log 9 = \log (3^2) = 2 \log 3$ So: $2^{\log 9} = 2^{2 \log 3} = (2^{\log 3})^2$ Since $2^{\log 3} = 3$, we get: $(2^{\log 3})^2 = 3^2 = 9$

5. Subtract the last term: $22500 - 9 = 22491$

Given the choices, it seems the problem may have intended different properties of logarithms or base conversions, but assuming the straightforward interpretation above:

$\boxed{22491}$

However, none of the provided options match this result. The provided answer choices might indicate a different expected approach, such as base manipulation or simplifications assumed in a different way. Double-check the problem context for further clues!